Part (i)
2 marksis the vector equation of a straight line: it passes through the point with position vector , and is parallel to (has direction) . As the parameter varies over all real numbers, traces out every point on this line.
Part (ii)
3 marksis the vector equation of a plane with unit normal vector : it consists of all points whose position vector has the same projection onto , namely .
Since is a unit vector, is the length of the projection of onto for any point on the plane, i.e. is the perpendicular distance from the origin to the plane.
Part (iii)
3 marksApproach
The point we want lies on both the line and the plane, so we substitute the line’s equation for into the plane’s equation and solve for .
Substituting into :
Since , we may divide by it:
Substituting back into :
Since , the line is not parallel to the plane, so it meets the plane at exactly one point.
, the position vector of that unique point of intersection.