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2023 A-Level · Paper 2 · Question 7

2023 H2 Maths Paper 2, Question 7

Correlation and Regression 7 marks Regression Lines
Download Paper 2 solutions (PDF)

Part (a)(i)

1 mark
r=0.9281 (4 d.p.)r = 0.9281\ \left( 4\text{ d.p.} \right)

Explanation: By GC, entering the eight pairs (x,y)(x,y) into linear regression statistics gives the product moment correlation coefficient between xx and yy.

Part (a)(ii)

1 mark
r=0.9697 (4 d.p.)r = 0.9697\ \left( 4\text{ d.p.} \right)

Explanation: By GC, entering the pairs (x,ey)\left( x,e^{y} \right) — where each eye^{y} is computed from the table, e.g. e3.99≈54.05e^{3.99} \approx 54.05 and e8.39≈4402.82e^{8.39} \approx 4402.82 — gives the product moment correlation coefficient between xx and eye^{y}.

Part (b)

3 marks

Since r=0.9697r = 0.9697 (between xx and eye^{y}) is closer to 11 than r=0.9281r = 0.9281 (between xx and yy), the model ey=cx+de^{y} = cx + d gives a better (stronger linear) fit to the data than y=ax+by = ax + b.

By GC, the regression line of eye^{y} on xx has

c≈375.615,d≈−1881.48c \approx 375.615,\quad d \approx - 1881.48

Note: xˉ=11\bar{x} = 11, the midpoint of the evenly spaced values x=4,6,…,18x = 4,6,\ldots,18, as expected.

∴ ey=375.6x−1881\therefore\ e^{y} = 375.6x - 1881 (coefficients to 4 s.f.)

Part (c)

2 marks

Approach

We substitute x=24x = 24 into the regression equation of eye^{y} on xx from part (b), then take ln⁡\ln to recover yy, and finally comment on reliability by checking whether x=24x = 24 lies inside the data range used to fit the line.

For the year 20242024, x=2024−2000=24x = 2024 - 2000 = 24.

ey=375.615(24)−1881.48e^{y} = 375.615(24) - 1881.48
≈7133.28\approx 7133.28
y=ln⁡(7133.28)y = \ln(7133.28)
≈8.87\approx 8.87
To check your answer: 8.878.87 million is only a modest rise from the last data point (8.398.39 million in 2018), consistent with the flattening trend visible for large xx ✓

Since x=24x = 24 lies outside the range of the given data (x=4x = 4 to x=18x = 18), using the regression equation here means extrapolating beyond the data range. There is no guarantee the same relationship continues to hold there, so the estimate is not necessarily reliable.

∴\therefore the estimated number of subscriptions in 2024 is approximately 8.878.87 million, but this estimate is not necessarily reliable since it requires extrapolation.

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