Approach: the deposits form an arithmetic progression; because the condition is “at least ” and is wanted to the nearest cent, we solve the equality first and then check whether rounding up or down is what actually satisfies the inequality.
From 31 January 2021 to 31 December 2023 is exactly 3 years, i.e. monthly deposits, forming an arithmetic progression with first term , common difference , and terms.
Requiring ,
Since is to the nearest cent, we must round up (rounding down would leave ).
To check your answer: at , ; at , — confirming is indeed the smallest cent value that works. ✓
the smallest value of is .
Part (b)
3 marks
Approach: set up a recurrence for the amount owed, unroll it for the first few months to see the pattern, then sum the resulting geometric series in general.
Let be the amount owed after months. Each month, interest of is added first, then the repayment is subtracted:
Applying this repeatedly,
In general,
The bracketed term is a geometric series of terms with first term and common ratio :
Substituting back,
To check your answer: at , the formula gives , matching the recurrence directly. ✓
as required. (shown)
Part (c)(i)
4 marks
For the loan to be fully repaid in months, :
the monthly repayment is (nearest cent).
Part (c)(ii)
Using the rounded repayment from (c)(i), the total repaid over months is . The total interest paid is this total minus the original loan amount:
the total interest paid is .
Part (d)(i)
4 marks
Approach: with a fixed payment, use the formula from (b) to write explicitly, find the (non-integer) at which , and note that Wei cannot overpay — so she pays for the largest whole number of months that still leaves a positive balance, then clears the rest with a smaller final payment .
With in the formula from (b),
is decreasing (since grows), reaching when
Since is not a whole number, Wei makes full payments of , leaving a small positive balance that is cleared by a smaller final payment.
Note: a th payment of would overpay, since .
The final repayment clears this balance after one more month’s interest is added:
To check your answer: as required; a further payment at month instead would give , i.e. an overpayment, confirming and not . ✓
and .
Part (d)(ii)
The total repaid under the plan in (d)(i):
The total repaid under the plan in (c)(i):
Wei saves approximately (4 s.f.) by making the repayments in (d)(i) rather than in (c)(i).
This is how we mark, and how we teach.
Every Ten-Year Series question, worked in full, with the reasoning written out and the traps named.